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4r^2-7r-15=0
a = 4; b = -7; c = -15;
Δ = b2-4ac
Δ = -72-4·4·(-15)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-17}{2*4}=\frac{-10}{8} =-1+1/4 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+17}{2*4}=\frac{24}{8} =3 $
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